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Partial fractions

A fraction with a factorised denominator can be written as a sum of simpler fractions. For two linear factors with numerator 1 the coefficients are 1 and −1-1. You check by using a common denominator, or by inserting a number where the denominator is not zero. The integral of each partial fraction is a logarithm. The method is used when substitution and integration by parts do not fit.

1x(x+1)=1x−1x+1\frac{1}{x(x+1)} = \frac{1}{x} - \frac{1}{x+1}partial fractions
∫1x(x+1) dx=ln⁡∣x∣−ln⁡∣x+1∣+C\int\frac{1}{x(x+1)}\,dx = \ln|x| - \ln|x+1| + Cthe integral

Symbols

xxthe variable

Example

At x=2x = 2, 12⋅3=16\dfrac{1}{2\cdot 3} = \dfrac{1}{6} and 12−13=16≈0.1667\dfrac{1}{2} - \dfrac{1}{3} = \dfrac{1}{6} \approx 0.1667.

Check the splitting with a number before you integrate. The common denominator should give back the original fraction.
Practise integration techniques for free →

← Integration by parts of xe^x · Area between graphs →

Part of Mathematics R2: Integration techniques.