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Direct proof

A direct proof starts from what you know and works its way to the claim. Three consecutive integers can be written nn, n+1n + 1 and n+2n + 2. The sum becomes 3(n+1)3(n + 1), which is always divisible by 3. The same setup solves a number problem: if the sum is known, the middle number is the sum divided by 3. The proof holds for every integer, not only for one example.

n+(n+1)+(n+2)=3(n+1)n + (n+1) + (n+2) = 3(n+1)the sum of three consecutive integers

Symbols

nnthe smallest of the numbers

Example

The sum 13+14+15=4213 + 14 + 15 = 42. In general the middle number is 423=14\dfrac{42}{3} = 14, and the sum 3(n+1)3(n + 1) is divisible by 33.

An example illustrates the claim. The proof must hold for an arbitrary integer nn.
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Part of Mathematics R1: Logic and proof.