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The remainder theorem

When you divide the polynomial P(x)P(x) by x−ax - a, the remainder is the number P(a)P(a). You do not need to carry out the whole division to find the remainder. If P(a)=0P(a) = 0, the division is exact and x−ax - a is a factor. Integer zeros of a polynomial with integer coefficients and leading coefficient 1 must divide the constant term, so those are the values you try first.

P(x)=(x−a)Q(x)+P(a)P(x) = (x - a)Q(x) + P(a)the remainder is P(a)P(a)
P(a)=0  ⟺  (x−a) is a factorP(a) = 0 \iff (x - a)\ \text{is a factor}a zero gives a factor

Symbols

aathe number you divide by, in x−ax - a
P(a)P(a)the remainder

Example

P(x)=x3+2x−5P(x) = x^3 + 2x - 5 divided by x−1x - 1: the remainder is P(1)=1+2−5=−2P(1) = 1 + 2 - 5 = -2.

Evaluate P(a)P(a) directly. Then you skip the whole division when you only need the remainder.
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Part of Mathematics 1T: Factorisation and polynomial division.