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Equations with x in the exponent

When the unknown is in the exponent, take the logarithm of both sides and use lg⁡bx=xlg⁡b\lg b^x = x\lg b. First isolate the power so that it stands alone. If both sides are powers with the same base, you can instead set the exponents equal. A logarithmic equation can only have solutions that make the arguments positive.

Try it yourself

Exponential growth

a⋅bx=c⇒x=lg⁡(c/a)lg⁡ba\cdot b^x = c \Rightarrow x = \frac{\lg(c/a)}{\lg b}the solution
bx=bk⇒x=kb^x = b^k \Rightarrow x = kthe same base

Symbols

bbthe base, positive and not 1
xxthe exponent

Example

500⋅1.04x=800500\cdot 1.04^x = 800 gives 1.04x=1.61.04^x = 1.6 and x=lg⁡1.6lg⁡1.04≈12.0x = \dfrac{\lg 1.6}{\lg 1.04} \approx 12.0. 2x=322^x = 32 gives x=5x = 5, since 25=322^5 = 32.

Divide out the constant in front of the power before you take the logarithm.
Practise powers, roots and logarithms for free →

← Common logarithms · Growth factor →

Part of Mathematics 1T: Powers, roots and logarithms.