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Depreciation

When an object loses the same percentage of its value every year, the model is exponential with a growth factor less than 1. You do not multiply by the percentage, but by what remains. If a car loses 15% per year, the factor is 0.850.85, and the value after xx years is the initial value times 0.85x0.85^x. The factor should be positive. A negative factor would change sign every year.

V(x)=a⋅bxV(x) = a\cdot b^xvalue after x years
b=1−p100b = 1 - \frac{p}{100}factor for a loss of p percent

Symbols

VVthe valuekr
aaprice when newkr
xxageyears

Example

A car costing 400 000 kr loses 15% per year, so b=1−0.15=0.85b = 1 - 0.15 = 0.85. After 4 years: 400 000⋅0.854≈208 800400\,000\cdot 0.85^4 \approx 208\,800 kr.

A 15% loss of value means that 85% of the value remains, not that you subtract 15.
Practise exponential models for free →

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Part of Mathematics 1T: Exponential models.