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Hydraulic press

Pascal's principle says the pressure in a closed, connected fluid is equal everywhere. In a hydraulic press this gives a force amplification: a small force on a small piston creates the same pressure as a much larger force on a large piston, because pressure is force divided by area.

p=F1A1=F2A2p = \dfrac{F_1}{A_1} = \dfrac{F_2}{A_2}equal pressure on both pistons
F2=F1A2A1F_2 = F_1\dfrac{A_2}{A_1}force amplification

Symbols

F1, F2F_1,\ F_2forces on the two pistonsN
A1, A2A_1,\ A_2areas of the pistonsm²

Example

A hydraulic jack has A1=5A_1 = 5 cm² and A2=150A_2 = 150 cm². A force F1=100F_1 = 100 N gives F2=100⋅150/5=3000F_2 = 100\cdot 150/5 = 3000 N.

The force amplification costs you displacement – the small piston must move much farther than the large one.
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Part of Fluid Mechanics: Hydrostatics.