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Superposition

In a linear circuit with several independent sources you can find the current or voltage in a branch by adding the contribution from each source acting alone. To do this you turn off all the other sources: a voltage source is shorted to 0 V, and a current source is opened to 0 A. The method never applies directly to power, since power is quadratic in current and voltage.

I=I′+I′′+…I=I'+I''+\dotstotal current is the sum of contributions from each source alone

Symbols

I′I'contribution from source 1 (other sources off)A
I′′I''contribution from source 2 (other sources off)A

Example

U1=12U_1=12 V gives I′=1.2I'=1.2 A, I2=2I_2=2 A gives I′′=0.8I''=0.8 A:

I=I′+I′′=1.2+0.8=2I=I'+I''=1.2+0.8=2 A.

Turn off sources by shorting voltage sources and opening current sources – never the other way around.
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Part of Electric Circuits: Network analysis.