All courses › Statistics and Risk Analysis › Union, intersection and complement

Union, intersection and complement

For two events AA and BB, the union rule gives the probability that at least one of them occurs; the intersection A∩BA\cap B must be subtracted so it is not counted twice. The complement AcA^c is useful for "at least one" questions, since it is often easier to compute the opposite event.

P(A∪B)=P(A)+P(B)−P(A∩B)P(A\cup B) = P(A) + P(B) - P(A\cap B)probability of AA or BB
P(Ac)=1−P(A)P(A^c) = 1 - P(A)the complement rule

Symbols

A∪BA\cup BAA or BB (or both)
A∩BA\cap BAA and BB together
AcA^cthe complement of AA (not AA)

Example

P(A)=0.45P(A) = 0.45, P(B)=0.65P(B) = 0.65, P(A∩B)=0.15P(A\cap B) = 0.15:

P(A∪B)=0.45+0.65−0.15=0.95P(A\cup B) = 0.45 + 0.65 - 0.15 = 0.95.

"At least one of nn" is often easiest to find as 1−1 - the probability that none occur.
Practise probability for free →

Series and parallel systems →

Part of Statistics and Risk Analysis: Probability.